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v5.0
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    v5.0

      UNION ALL

      Overview

      The UNION ALL statement combines results of two or more queries into a single result set that includes all records present in any of the query.

      To remove duplicate records during a union operation, use the UNION statement.

      Syntax

      ...
      return <item1> as <alias1?>, <item2?> as <alias2?>, ...
      union all
      ...
      return <item1> as <alias1?>, <item2?> as <alias2?>, ...
      

      Details

      • The return items in all queries combined by UNION ALL must be identical.

      Example Graph

      To create the graph, execute each of the following UQL queries sequentially in an empty graphset:

      create().node_schema("student").node_schema("course").edge_schema("takes")
      create().node_property(@*, "name").node_property(@student, "age", int32).node_property(@course, "credits", int32)
      insert().into(@student).nodes([{_id:"S1", name:"Jason", age:25}, {_id:"S2", name:"Lina", age:23}, {_id:"S3", name:"Eric", age:24}, {_id:"S4", name:"Emma", age:26}, {_id:"S5", name:"Pepe", age:24}])
      insert().into(@course).nodes([{_id:"C1", name:"French", credits:4}, {_id:"C2", name:"Math", credits:5}])
      insert().into(@takes).edges([{_from:"S1", _to:"C1"}, {_from:"S2", _to:"C1"}, {_from:"S3", _to:"C1"}, {_from:"S2", _to:"C2"}, {_from:"S3", _to:"C2"}, {_from:"S4", _to:"C2"}, {_from:"S5", _to:"C2"}])
      

      Combining Queries

      n({@course.name == "French"}).e().n({@student} as s) return s.name
      union all
      n({@course.name == "Math"}).e().n({@student} as s) return s.name
      

      Result:

      s.name
      Lina
      Eric
      Jason
      Lina
      Emma
      Eric
      Pepe
      n({@course.name == "French"} as c).e().n({@student} as s) return c.name, s.age 
      union all
      n({@course.name == "Math"} as c).e().n({@student} as s) return c.name, s.age
      

      Result:

      c.name s.age
      French 23
      French 24
      French 25
      Math 23
      Math 26
      Math 24
      Math 24
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