Overview

The ORDER BY statement sorts records based on a set of keys. When multiple keys are provided, sorting is applied sequentially from left to right: first by the first key, then by the second key for records with identical first key values, and so on.

Syntax

ORDER BY <key1> <desc_asc?>, <key2?> <desc_asc?>, ...

Details

• <key>: The sorting key which references an alias declared in previous statements.
• <desc_asc?>: The ordering specification, which is ASC (ascending) or DESC (descending). It's optional and ASC is applied by default.
• The null values are excluded from the sorting process, and their corresponding records are placed at the end of the sorted results.

Example Graph

To create the graph, execute each of the following UQL queries sequentially in an empty graphset:

create().node_schema("student").node_schema("course").edge_schema("takes")
create().node_property(@*, "name").node_property(@student, "age", int32).node_property(@course, "credits", int32)
insert().into(@student).nodes([{_id:"S1", name:"Jason", age:25}, {_id:"S2", name:"Lina", age:23}, {_id:"S3", name:"Eric", age:24}, {_id:"S4", name:"Emma", age:26}, {_id:"S5", name:"Pepe", age:24}])
insert().into(@course).nodes([{_id:"C1", name:"French", credits:4}, {_id:"C2", name:"Math", credits:5}])
insert().into(@takes).edges([{_from:"S1", _to:"C1"}, {_from:"S2", _to:"C1"}, {_from:"S3", _to:"C1"}, {_from:"S2", _to:"C2"}, {_from:"S3", _to:"C2"}, {_from:"S4", _to:"C2"}, {_from:"S5", _to:"C2"}])

Ordering by Property

find().nodes({@student}) as stu
order by stu.age desc
return table(stu.name, stu.age)

Result:

Ordering by Node/Edge Alias

When a node or edge alias is specified as the sorting key, the records are sorted on the _uuid of the nodes or edges.

find().nodes({@student}) as stu
order by stu
return table(stu.name, stu._uuid)

Result:

Ordering by Expression

n({name == "Jason"}).e()[:3].n() as p
order by length(p)
return p{*}

Jason -> French
Jason -> French <- Lina
Jason -> French <- Eric
Jason -> French <- Lina -> Math
Jason -> French <- Eric -> Math

Multi-level Ordering

n({@course} as crs).e().n({@student} as stu) as p
order by crs.credits, stu.age desc 
return table(crs.name, crs.credits, stu.name, stu.age)

Result:

Grouping and Ordering

To count the number of students enrolled in each course and sort the results by the count:

n({@course} as crs).e().n({@student})
group by crs
with crs, count(crs) as stuCnt
order by stuCnt desc 
return table(crs.name, stuCnt)

Result: