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      ORDER BY

      ORDER BY adjusts the order of rows in the data stream.

      Syntax: ORDER BY <expression> <string>, <expression> <string>, ...
      Input:

      • <expression>: Sorting basis; multiple bases must be homologous and are operated from left to right
      • <alias>: Fashion of sorting, either asc or desc (case insensitive), or asc when omitted
      find().nodes([4, 2]) as nodes
      n(nodes).e().n(as n) as path
      order by n.radius desc, n
      return path
      

      In the UQL above, ORDER BY adjusts the order of the one-step paths resulted from template query, first by radius of terminal nodes n in descending order, then by ID of terminal nodes n that share the same radius in ascending order.

      ATTR (Numeric value)

      Example: Find 10 cards that have the highest balances, i.e, sorts the card balances in a descending order

      find().nodes({@card}) as n
      order by n.balance desc 
      return n{*} limit 10
      

      ATTR (Time)

      Example: Find cards of Customer CU001, return cards' info in an ascending time order

      n({_id == "CU001"}).re({@has}).n({@card} as n)
      order by n.open_date
      return n{*}
      

      ATTR (String)

      Example: Find 10 email addresses, sort them in a descending order of letters from addresses

      find().nodes({@email}) as n
      limit 10
      order by n.address desc 
      return n{*}
      

      NODE

      Example: Find 10 two-step transfer paths, sort paths in a descending order of 2nd nodes' UUIDs

      n({@card}).e({@transfer}).n({@card} as n)
        .e({@transfer}).n({@card}) as p
      limit 10
      order by n desc
      return p{*}
      

      EDGE

      Example: Find 10 two-step transfer paths, sort paths in a descending order of the 2nd edges' UUIDs

      n({@card}).e({@transfer}).n({@card})
        .e({@transfer} as e).n({@card}) as p
      limit 10
      order by e desc
      return p{*}
      

      GROUP BY and ORDER BY

      Example: Sort all cards in groups by their levels, count the number of cards at each level, return the 3 levels with the most cards and card numbers at these levels

      find().nodes({@card}) as n
      group by n.level as level
      return level, count(n) as total limit 3
      order by total desc
      
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